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    Vb colors as strings

    I have a dropdown list in a sheet from which the user will select a color (the 7 constants) red, cyan...
    In my code I wanted to simply put "vb" before it something like:
    Code:
    xcolor = "vb" & user-selected-color
    cells(x,y).interior.color = xcolor
    But it fails to produce the color. Any ideas? Is there something that evaluates a string "vbred" as vbred?
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    Re: Vb colors as strings

    You can use select case.

    Note since the variable is using ucase to make it all upper case in the select case the color name needs to be all upper case.

    Code:
    Sub colorcell()
    
    Dim mycolor As String
    
    
    mycolor = UCase(Range("A1"))
    
    
    Select Case mycolor
    
    
    Case "RED"
    Range("A3").Interior.Color = vbRed
    
    
    Case "BLUE"
    Range("A3").Interior.Color = vbBlue
    
    
    Case "YELLOW"
    Range("A3").Interior.Color = vbYellow
    
    
    'other colors here
    
    
    
    
    End Select
    
    
    End Sub
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    Re: Vb colors as strings

    I'm assuming you want to use this in a sheet change event script

    Assuming you will be using this in column (5) Modify if needed
    Try this:

    You should put these values in a DataValidation list

    Black,White,Red,Green,Blue,Yellow,Magenta,Cyan



    Code:
    Private Sub Worksheet_Change(ByVal Target As Range)
    'Modified 12-1-17 11:00 PM EST
    If Target.Column = 5 Then
    Dim MyColor As String
    MyColor = Target.Value
        With Target.Interior
        Select Case MyColor
            Case "Red"
                .Color = vbRed: Target.Value = ""
                    Case "Red"
                        .Color = vbRed: Target.Value = ""
                    Case "Black"
                        .Color = vbBlack: Target.Value = ""
                    Case "White"
                        .Color = vbWhite: Target.Value = ""
                    Case "Green"
                        .Color = vbGreen: Target.Value = ""
                    Case "Blue"
                        .Color = vbBlue: Target.Value = ""
                    Case "Yellow"
                        .Color = vbYellow: Target.Value = ""
                    Case "Magenta"
                        .Color = vbMagenta: Target.Value = ""
                    Case "Cyan"
                        .Color = vbCyan: Target.Value = ""
        End Select
    End With
    End If
    End Sub
    Last edited by My Aswer Is This; Dec 1st, 2017 at 11:06 PM.
    Be sure and always test this script on sample data the first time you use this as to avoid any problems with your dataSlouch Boots Clarks Caddell Women’s Black Synthetic Black Sloane qFFtH. Always trying to learn more and help others where I can. I'm using Excel 2013.
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    Re: Vb colors as strings

    Assuming your data validation list is

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    Black,White,Red,Green,Blue,Yellow,Magenta,Cyan

    Then this worksheet change code should work. This is using Column E (5)

    Code:
    Private Sub Worksheet_Change(ByVal Target As Range)
    Dim arrColors, vbaColors, lngIndex As Long
    arrColors = Array("Black", "White", "Red", "Green", "Blue", "Yellow", "Magenta", "Cyan")
    vbaColors = Array(vbBlack, vbWhite, vbRed, vbGreen, vbBlue, vbYellow, vbMagenta, vbCyan)
    If Target.Column <> 5 Then Exit Sub
    If Target <> "" Then lngIndex = Application.Match(Target, arrColors, 0) - 1: Target.Interior.Color = vbaColors(lngIndex)
    End Sub
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    Re: Vb colors as strings

    Originally Posted by Scott Huish
    Assuming your data validation list is

    Black,White,Red,Green,Blue,Yellow,Magenta,Cyan

    Then this worksheet change code should work. This is using Column E (5)

    Code:
    Private Sub Worksheet_Change(ByVal Target As Range)
    Dim arrColors, vbaColors, lngIndex As Long
    arrColors = Array("Black", "White", "Red", "Green", "Blue", "Yellow", "Magenta", "Cyan")
    vbaColors = Array(vbBlack, vbWhite, vbRed, vbGreen, vbBlue, vbYellow, vbMagenta, vbCyan)
    If Target.Column <> 5 Then Exit Sub
    If Target <> "" Then lngIndex = Application.Match(Target, arrColors, 0) - 1: Target.Interior.Color = vbaColors(lngIndex)
    End Sub
    I like this array approach best. Thanks everyone.
    I was hoping there was just a simple function that would turn "red" into vbred. I think I'll create a ud function for this.
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    Re: Vb colors as strings

    Originally Posted by Roderick_E
    I like this array approach best. Thanks everyone.
    I was hoping there was just a simple function that would turn "red" into vbred. I think I'll create a ud function for this.
    Black Bogs Boots Chukka Chukka Boots Bogs Boots Johnny Black Johnny Chukka Johnny Bogs Code:
    Function xlcolors(color As String)
    Dim arrColors, vbaColors, lngIndex As Long
    arrColors = Array("Black", "White", "Red", "Green", "Blue", "Yellow", "Magenta", "Cyan")
    vbaColors = Array(vbBlack, vbWhite, vbRed, vbGreen, vbBlue, vbYellow, vbMagenta, vbCyan)
    'cell colors
    lngIndex = Application.Match(color, arrColors, 0) - 1
    xlcolors = vbaColors(lngIndex)
    End Function
    Bogs Black Chukka Boots Boots Chukka Bogs Chukka Black Johnny Boots Bogs Johnny Johnny Code:
    sub test
    activecell.interior.color = xlcolors("Red")
    end sub
    could also do activecell.font.color = xlcolors("Red")

    This is for when "Red" is a dynamic or what's in arrColors otherwise you could just use activecell.XXX = vbred

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    Re: Vb colors as strings

    I would add an On Error Resume Next to that:

    Code:
    Function xlcolors(color As String)
    On Error Resume Next
    Dim arrColors, vbaColors, lngIndex As Long
    arrColors = Array("Black", "White", "Red", "Green", "Blue", "Yellow", "Magenta", "Cyan")
    vbaColors = Array(vbBlack, vbWhite, vbRed, vbGreen, vbBlue, vbYellow, vbMagenta, vbCyan)
    'cell colors
    lngIndex = Application.Match(color, arrColors, 0) - 1
    xlcolors = vbaColors(lngIndex)
    End Function
    It will return the first color in the Array if an improper color is passed and not error out:

    Code:
    Sub test()
    ActiveCell.Font.color = xlcolors("Orange")
    End Sub
    Office 2010/365

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